Question
Mathematics Question on geometric progression
Given a G.P. with a = 729 and 7th term 64, determine S7.
Answer
a = 729
a7 = 64
Let r be the common ratio of the G.P.
It is known that, an = a r n-1
a7 = ar7-1 = (729)r 6
⇒ 64 = 729 r 6
⇒r6=72964
⇒r6=(32)6
⇒r=32
Also, it is known that, Sn=1−ra(1−rn)
∴S7=1−32729[1−(32)7]
=3×729[1−(32)7]
=(3)[(3)7(3)7−(2)7]
=(3)7−(2)7
=2187−128
=2059