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Chemistry Question on Coordination Compounds

Give the oxidation state, d-orbital occupation and coordination number of the central metal ion in the following complexes:
(i) K3[Co(C2O4)3]K_3[Co(C_2O_4)_3]
(ii)cis[Cr(en)2Cl2]Clcis-[Cr(en)_2Cl_2]Cl
(iii) (NH4)2[CoF4](NH_4)_2[CoF_4]
(iv) [Mn(H2O)6]SO4[Mn(H_2O)_6]SO_4

Answer

(i) K3[Co(C2O4)3]K_3[Co(C_2O_4)_3]
The central metal ion is Co.Co.
Its coordination number is 66.
The oxidation state can be given as:
x6=3x-6 =-3
x=+3x =+3
The d orbital occupation forCo3+ Co^{ 3+} is t2g6eg0.t_{2g}^{ 6}e_g^{0}.

(ii) cis[Cr(en)2Cl2]Clcis-[Cr(en)_2Cl_2]Cl
The central metal ion is Cr.Cr.
The coordination number is 6.6.
The oxidation state can be given as:
x+2(0)+2(1)=+1x+2(0)+2(-1)=+1
x2=+1x - 2 = +1
x=+3x = +3
The d orbital occupation for Cr3+Cr^{3+} is t2g3.t_{2g}^{3} .

(iii) (NH4)2[CoF4](NH_4)_2[CoF_4] The central metal ion isCo.Co.
The coordination number is 4.4.
The oxidation state can be given as:
x4=2x-4 =-2
x=+2x=+2 The d orbital occupation for Co2+Co^{2+} is eg4  t2g3.e_g^{4}\space t_{2g} ^{3}.

(iv) [Mn(H2O)6]SO4[Mn(H_2O)_6]SO_4 The central metal ion is Mn.Mn.
The coordination number is 66.
The oxidation state can be given as:
x+0=+2x+0=+2
x=+2x=+2 The d orbital occupation for MnMn is t2g3  eg2.t_{2g}^{3}\space e_g^{2} .