Question
Question: Give reason: \(P\) in \(PC{l_5}\) and \(S\) in \(S{F_6}\) having \(10\) electrons and \(12\) electro...
Give reason: P in PCl5 and S in SF6 having 10 electrons and 12 electrons in their valence shell.
Solution
It will be better to write the electronic configurations of the individual element phosphorus P and Sulphur S. Then try to draw the structures of PCl5 and SF6 using the basics of chemical bonding.
Complete answer:
First, we will write the electronic configuration of the individual element P and Sulphur S . So the electronic configuration for the two elements can be written as follows:
The total number of electrons present in Phosphorus is 15. So, the electronic configuration can be written as.
P→1s22s22p63s23p33d0
The total number of electrons present in Sulphur is 16. So, the electronic configuration can be written as.
S→1s22s22p63s23p43d0
The molecule PCl5 is formed by sharing one electron each with five chlorine atoms. We know that there are five electrons in the valence shell of phosphorus. But in phosphorus pentachloride PCl5 chlorine has eight electrons with a complete octet. But P now have 10 electrons. Five electrons of phosphorus with the addition of five shared electrons with chlorine.
Now we will consider SF6 which Sulphur with six electrons in the valence shell.
The molecule SF6 is formed by sharing one electron each with six fluorine atoms.We know that there are six electrons in the valence shell of Sulphur. But in SF6 fluorine have eight electrons with a complete octet. But S have 12 electrons. Six electrons of Sulphur with the addition of six shared electrons with fluorine.
Note:
In several compounds of the third period and beyond the third period there are more than eight valence electrons around the central atom. This condition is the limitation of octet rule also known as an expanded octet.
According to the octet rule, atoms can combine by sharing or transfer of electrons from one atom to another to complete their octet simply means eight electrons around the central atom.