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Question: give me analysis of a cubic f(x) when f'(x) = 0...

give me analysis of a cubic f(x) when f'(x) = 0

Answer

The analysis of a cubic function f(x)=ax3+bx2+cx+df(x) = ax^3 + bx^2 + cx + d when f(x)=0f'(x) = 0 depends on the discriminant of the resulting quadratic equation 3ax2+2bx+c=03ax^2 + 2bx + c = 0. Let Δ=4b212ac\Delta = 4b^2 - 12ac.

  1. If Δ>0\Delta > 0, f(x)f(x) has two distinct turning points (one local maximum and one local minimum).
  2. If Δ=0\Delta = 0, f(x)f(x) has one critical point which is a point of inflection with a horizontal tangent (no local maxima or minima).
  3. If Δ<0\Delta < 0, f(x)f(x) has no critical points where f(x)=0f'(x)=0, meaning it is strictly monotonic (always increasing or always decreasing) and has no local maxima or minima.
Explanation

Solution

For a cubic function f(x)=ax3+bx2+cx+df(x) = ax^3 + bx^2 + cx + d, where a0a \neq 0, the condition f(x)=0f'(x) = 0 is used to find its critical points, which are potential locations for local maxima, local minima, or points of inflection with a horizontal tangent.

  1. First Derivative: Calculate the first derivative of the cubic function: f(x)=ddx(ax3+bx2+cx+d)=3ax2+2bx+cf'(x) = \frac{d}{dx}(ax^3 + bx^2 + cx + d) = 3ax^2 + 2bx + c

  2. Set f(x)=0f'(x) = 0: This yields a quadratic equation: 3ax2+2bx+c=03ax^2 + 2bx + c = 0 The roots of this quadratic equation are the x-coordinates of the critical points of f(x)f(x).

  3. Analyze the Discriminant (Δ\Delta) of the Quadratic Equation: The discriminant of the quadratic equation 3ax2+2bx+c=03ax^2 + 2bx + c = 0 is Δ=(2b)24(3a)(c)=4b212ac\Delta = (2b)^2 - 4(3a)(c) = 4b^2 - 12ac. The value of Δ\Delta determines the nature of the critical points and, consequently, the shape of the cubic function.

    • Case 1: Δ>0\Delta > 0 (i.e., 4b212ac>0    b23ac>04b^2 - 12ac > 0 \implies b^2 - 3ac > 0)

      • Nature of Critical Points: The quadratic equation f(x)=0f'(x) = 0 has two distinct real roots. These two roots correspond to two distinct turning points of the cubic function: one local maximum and one local minimum.
      • Function Behavior: The function changes its direction of monotonicity twice.
        • If a>0a > 0, the function increases, then decreases (local maximum), then increases (local minimum).
        • If a<0a < 0, the function decreases, then increases (local minimum), then decreases (local maximum).
      • Graph: The graph has the characteristic "S" shape with two distinct "bumps" (turning points).
    • Case 2: Δ=0\Delta = 0 (i.e., 4b212ac=0    b23ac=04b^2 - 12ac = 0 \implies b^2 - 3ac = 0)

      • Nature of Critical Points: The quadratic equation f(x)=0f'(x) = 0 has exactly one real root (a repeated root). This root corresponds to a point of inflection where the tangent is horizontal. This point is neither a local maximum nor a local minimum.
      • Function Behavior: The function does not change its direction of monotonicity at this point; its slope momentarily becomes zero.
        • If a>0a > 0, the function is strictly increasing (except at the inflection point where the slope is zero).
        • If a<0a < 0, the function is strictly decreasing (except at the inflection point where the slope is zero).
      • Graph: The graph has a "stretched S" shape, where the two turning points have merged into a single horizontal inflection point. There are no local maxima or minima.
    • Case 3: Δ<0\Delta < 0 (i.e., 4b212ac<0    b23ac<04b^2 - 12ac < 0 \implies b^2 - 3ac < 0)

      • Nature of Critical Points: The quadratic equation f(x)=0f'(x) = 0 has no real roots. This means f(x)f'(x) is never zero.
      • Function Behavior: The function is strictly monotonic (it never changes its direction of monotonicity and its slope is never zero).
        • If a>0a > 0, the function is strictly increasing for all xx.
        • If a<0a < 0, the function is strictly decreasing for all xx.
      • Graph: The graph does not have any turning points. It still has an inflection point (where f(x)=0f''(x) = 0), but the tangent at this point is not horizontal. There are no local maxima or minima.