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Question

Chemistry Question on Electrochemistry

Give: E0Mn+7|Mn+2 = 1.5 V and E0Mn+4|Mn+2 = 1.2 V, then E0Mn+7|Mn+4 is

A

1.7 V

B

2.1 V

C

0.3 V

D

0.1 V

Answer

1.7 V

Explanation

Solution

Mn+7+5eMn2+Mn^{+7} +5e^{-} \to Mn^{2+}
Mn+4+2eMn2+Mn^{+4}+2e^{-} \to Mn^{2+}
RequiredequationRequired \, equation
Mn+7+3eMn4+Mn^{+7}+3e^{-} \to Mn^{4+}
3FE=7.5F+2.4F\therefore\, -3FE^{�-}=-7.5F+2.4F
E=1.7V\therefore\, E^{�-}=1.7 V
ΔG=5F1.5,\Delta G^{�-}=-5 F 1.5,
ΔG=2F1.2,\Delta G^{�-}=-2 F 1.2,
ΔG=3FE\Delta G^{�-}=-3FE^{�-}