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Question

Question: Give an example of a relation which is symmetry only....

Give an example of a relation which is symmetry only.

Explanation

Solution

Hint- In order to deal with this question we will first assume a set AA and find the relation RR on set AA further we will check each condition of reflexive, symmetry and transitive and according to it we will comment that our set is symmetry only.

Complete step-by-step answer:
Let A=1,2,3A = \\{ 1,2,3\\}
Let relation R on set A be
Let R=(1,2),(2,1)R = \\{ (1,2),(2,1)\\}
Now we will check the condition of reflexive
So as we know that if the relation is reflexive then (a,a)R(a,a) \in R for every a1,2,3a \in \\{ 1,2,3\\}
Since, (1,1),(2,2),(3,3)(1,1),(2,2),(3,3) doesn’t belongs to RR
R=(1,2),(2,1)R = \\{ (1,2),(2,1)\\} is not reflexive
Now we will check the condition of symmetry
So as we know that if the relation is symmetry if (a,b)R,(a,b) \in R,then (b,a)R(b,a) \in R
Since, (1,2)R,(2,1)R(1,2) \in R,(2,1) \in R
R=(1,2),(2,1)R = \\{ (1,2),(2,1)\\} is symmetry
At last we will check the condition of transitive
So as we know that to check whether transitive or not
If (a,b)R&(b,a)R,(a,b) \in R\& (b,a) \in R,then (a,c)R(a,c) \in R
If a = 1, b = 2a{\text{ }} = {\text{ }}1,{\text{ }}b{\text{ }} = {\text{ }}2 but there is no cc ( no third element)
Similarly, If a = 2, b = 1a{\text{ }} = {\text{ }}2,{\text{ }}b{\text{ }} = {\text{ }}1but there is no cc ( no third element)
Here, R=(1,2),(2,1)R = \\{ (1,2),(2,1)\\} is not transitive
Hence, relation R=(1,2),(2,1)R = \\{ (1,2),(2,1)\\} is symmetry only and it is not reflexive and transitive.

Note- For a relation RR in set AA. Relation is reflexive if (a,a)R(a,a) \in R for every aAa \in A, It would be symmetric if (a,b)R(a,b) \in R, then (b,a)R(b,a) \in R and transitive if (a,b)R&(b,c)R,(a,b) \in R\& (b,c) \in R, then (a,c)R(a,c) \in R. If a relation is reflexive, symmetric and transitive then it is an equivalence relation.