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Question: The figure shows isotherms of a real gas compared to an ideal gas. Which of the following figures co...

The figure shows isotherms of a real gas compared to an ideal gas. Which of the following figures correctly represents the behavior of Hydrogen gas at 25°C?

A

(a)

B

(b)

C

(c)

D

(d)

Answer

(a)

Explanation

Solution

The compressibility factor Z=PVnRTZ = \frac{PV}{nRT} describes the deviation of a real gas from ideal behavior (Z=1Z=1). For a van der Waals gas, Z=VVnbaRTVZ = \frac{V}{V-nb} - \frac{a}{RTV}. The term aRTV\frac{a}{RTV} accounts for attractive forces, while VVnb\frac{V}{V-nb} accounts for repulsive forces. The Boyle temperature (TBT_B) is where a gas behaves most ideally. For a van der Waals gas, TB=aRbT_B = \frac{a}{Rb}. For Hydrogen (H2H_2), a=0.244L2atm/mol2a = 0.244 \, \text{L}^2\text{atm/mol}^2 and b=0.0266L/molb = 0.0266 \, \text{L/mol}. Thus, TB=0.2440.0821×0.0266112KT_B = \frac{0.244}{0.0821 \times 0.0266} \approx 112 \, \text{K} (-161°C). At temperatures T>TBT > T_B, ZZ is always greater than 1, meaning the real gas pressure is always greater than the ideal gas pressure. Since 25°C (298 K) is much greater than TBT_B (112 K), Hydrogen gas will behave such that its isotherm is always above the ideal gas isotherm.