Question

Gaseous $N_2O_4$ dissociates into gaseous $NO_2$ according to the reaction $N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g )$ At $300\, K$ and $1\, atm$ pressure, the degree of dissociation of $N_2O_4$ is $0.2.$ If one mole of $N_2O_4$ gas is contained in a vessel, then the density of the equilibrium mixture is :

• A. 1.56 g/L
• B. 3.11 g/L
• C. 4.56 g/L
• D. 6.22 g/L

Answer 1

Answer: (B)

3.11 g/L

Answer 2

$P V=n R T \Rightarrow 1 \times V=1 \times 0.0821 \times 300$
$\Rightarrow V=24.63$
$d=\frac{\text { mass of mixture }}{\text { vol }}$
$=\frac{0.8 \times 92+0.4 \times 45}{24.63}=3.11\, gm /$ lit