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Question: Gas at pressure P<sub>o</sub> is contained in a vessel. If the masses of all the molecules are doubl...

Gas at pressure Po is contained in a vessel. If the masses of all the molecules are doubled and their speed is halved, the resulting pressure P will be equal to Gas at pressure Po is contained in a vessel. If the masses of all the molecules are doubled and their speed is halved, the resulting pressure P will be equal to Gas at pressure Po is contained in a vessel. If the masses of all the molecules are doubled and their speed is halved, the resulting pressure P will be equal t

A

2Po

B

Po/4

C

Po

D

Po/2

Answer

Po/2

Explanation

Solution

Po = 13\frac { 1 } { 3 } (mnv)vrms2\left( \frac{mn}{v} \right)v_{rms}^{2}

P = 13\frac { 1 } { 3 } (mnv)vrms2\left( \frac{m^{'}n}{v} \right){v^{'}}_{rms}^{2}

where m′ = 2m, vrms=vrms2v_{rms}^{'} = \frac{v_{rms}}{2}

putting the value

PPo=mvrms2mvrms2=2mmvrms4×vrms\frac{P}{P_{o}} = \frac{m^{'}{v^{'}}_{rms}^{2}}{mv_{rms}^{2}} = \frac{2m}{m}\frac{v_{rms}}{4 \times v_{rms}} = 12\frac{1}{2}

P = Po/2