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Question

Question: \(f(x) = |x|\) is...

f(x)=∣x∣f(x) = |x| is

A

g(x)=[x]g(x) = \lbrack x\rbrack

B

x∈R,x \in R,

C

{x∈R:g(f(x))≤f(g(x))}=\{ x \in R:g(f(x)) \leq f(g(x))\} =

D

None of these

Answer

g(x)=[x]g(x) = \lbrack x\rbrack

Explanation

Solution

lim⁡x→0ax−1a+x−a\lim _ { x \rightarrow 0 } \frac { a ^ { x } - 1 } { \sqrt { a + x } - \sqrt { a } }

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