Question
Question: F(x) =ln(cosx) is Even, Odd or periodic nature...
F(x) =ln(cosx) is Even, Odd or periodic nature
Even
Odd
Periodic
Even, Periodic
Solution
To determine the nature of the function F(x)=ln(cosx), we need to check its domain and then evaluate if it's even, odd, or periodic.
1. Domain of the function:
For F(x)=ln(cosx) to be defined, two conditions must be met:
- cosx must be defined, which is true for all real x.
- The argument of the logarithm must be positive: cosx>0.
The condition cosx>0 holds when x lies in intervals of the form (2nπ−2π,2nπ+2π) for any integer n.
For example, one such interval is (−2π,2π).
The domain of F(x) is D=⋃n∈Z(2nπ−2π,2nπ+2π).
2. Check for Even/Odd nature:
A function F(x) is even if F(−x)=F(x) for all x in its domain.
A function F(x) is odd if F(−x)=−F(x) for all x in its domain.
First, we check if the domain is symmetric about the origin. If x∈D, then cosx>0. Since cos(−x)=cosx, it implies cos(−x)>0. Thus, if x∈D, then −x∈D. The domain is symmetric about the origin, so the function can be even or odd.
Now, let's evaluate F(−x):
F(−x)=ln(cos(−x))
Since the cosine function is an even function, cos(−x)=cosx.
Therefore,
F(−x)=ln(cosx)
This is equal to F(x).
Since F(−x)=F(x), the function F(x)=ln(cosx) is an even function.
3. Check for Periodic nature:
A function F(x) is periodic if there exists a positive constant T such that F(x+T)=F(x) for all x in its domain. The smallest such T is called the period.
We know that the cosine function is periodic with a period of 2π, meaning cos(x+2π)=cosx.
Let's evaluate F(x+2π):
F(x+2π)=ln(cos(x+2π))
Since cos(x+2π)=cosx,
F(x+2π)=ln(cosx)
This is equal to F(x).
Since F(x+2π)=F(x), the function F(x)=ln(cosx) is a periodic function with a period of 2π.
Conclusion:
The function F(x)=ln(cosx) is both an even function and a periodic function.