Question
Question: f(x) = \(\left| \begin{matrix} 2\cos^{2}2x & \sin 2x & - \sin x \\ \sin 2x & 2\sin^{2}x & \cos x \\ ...
f(x) = 2cos22xsin2xsinxsin2x2sin2x−cosx−sinxcosx0The value of ∫0π/2f´(x)
dx is equal to
A
–2
B
–1
C
2
D
0
Answer
0
Explanation
Solution
∫0π/2f´(x)dx = f(2π) – f(0) = 201020−100 – 20000−1010
= 2 – 2 = 0