Question
Physics Question on Oscillations
Function x=Asin2ωt+Bcos2ωt+Csinωtcosωt represents SHM
A
For any value of A , B and C (except C = 0)
B
If A=−B,C=2B,amplitude=∣B2∣
C
If A=B;C=0
D
If A=b:C=2b,amplitude=∣B∣
Answer
If A=b:C=2b,amplitude=∣B∣
Explanation
Solution
For A = - B and C = 2B
X=Bcos2ωt+Bsin2ωt=2Bsin(2ωt+4π)
This is equation of SHM of amplitude 2B
.
If A = B and C = 2B , then X=B+Bsin2ωt
This is also equation of SHM about the point X = B. Function
oscillates between X = Oand X = 2B with amplitude B.