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Question

Mathematics Question on Heights and Distances

From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45° then the distance between two objects is 60

A

603 m60\sqrt 3\ m

B

(60+203) m(60+20\sqrt 3)\ m

C

60(31) m60(\sqrt 3-1)\ m

D

60(3+1) m60(\sqrt 3+1)\ m

Answer

60(3+1) m60(\sqrt 3+1)\ m

Explanation

Solution

The correct option is (D): 60(3+1) m60(\sqrt 3+1)\ m.