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Question

Physics Question on Motion in a plane

From the top of a tower, 80m80\, m high from the ground, a stone is thrown in the horizontal direction with a velocity of 8ms1.8\, ms^{-1}. The stone reaches the ground after a time ?t? and falls at a distance of ?d? from the foot of the tower. Assuming g=10ms2,g=10\, ms^{-2}, the time t and distance d are given respectively by

A

6 s, 64 m

B

6 s, 48 m

C

4 s, 32 m

D

4s, 16 m

Answer

4 s, 32 m

Explanation

Solution

Given, h=80m,v=8ms1h=80\, m ,\, v=8\, ms ^{-1} and g=10ms2g=10\, ms ^{-2}
Here,
h=12gt2h =\frac{1}{2} g t^{2}
80=12×10×t280 =\frac{1}{2} \times 10 \times t^{2}
t=4st =4\, s
and x=vt=8×4=32mx =v t=8 \times 4=32\, m