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Question: From the top of a lighthouse \[210\] feet high, the angle of depression of a boat is \[27\] degrees....

From the top of a lighthouse 210210 feet high, the angle of depression of a boat is 2727 degrees. How do you find the distance from the boat to the foot of the lighthouse where the lighthouse was built at sea level?

Explanation

Solution

Hint : To solve this question, first we will create a correct diagram taking the boat as a point and the lighthouse as a perpendicular line. Then convert the word problem into the mathematical equations. After that using the triangle properties of trigonometric ratios, we will find the distance from the boat to the foot of the lighthouse.
Property used:
tanθ=perpendicularbase\tan \theta = \dfrac{{perpendicular}}{{base}}

Complete step-by-step answer :
First, let’s create a correct diagram taking boat as a point and the lighthouse as a perpendicular line

Let A be the boat
BC be the light house which is equals to 210 feet210{\text{ feet}}
And XCA\angle XCA is the angle of depression of a boat which is equals to 2727^\circ
Now, we have to find the distance from the boat to the foot of the lighthouse which means we have to find the distance AB.
If we see a triangle formed by the lighthouse, the ground, and the boat.
And we know that the angle of depression is equal to the angle of elevation at the boat.
So, by using alternate interior angle property, we can say that
XCA=CAB=27\angle XCA = \angle CAB = 27^\circ
Now, we know that the sum of interior angle of a triangle is 180180^\circ
Therefore, ABC+BCA+CAB=180\angle ABC + \angle BCA + \angle CAB = 180^\circ
On substituting the values, we get
90+BCA+27=18090^\circ + \angle BCA + 27^\circ = 180^\circ
BCA=63\angle BCA = 63^\circ

Now, the distance of the boat is the side perpendicular to the angle of 6363^\circ while the height of the lighthouse is the base side.
And we know that
tanθ=perpendicularbase\tan \theta = \dfrac{{perpendicular}}{{base}}
Therefore, we get
tan63=AB210\tan 63^\circ = \dfrac{{AB}}{{210}}
AB=tan63×210\Rightarrow AB = \tan 63^\circ \times 210
Since tan63=1.963\tan 63^\circ = 1.963
Therefore, we get
AB=1.963×210\Rightarrow AB = 1.963 \times 210
AB=412.23 feet\Rightarrow AB = 412.23{\text{ feet}}
Hence, the distance from the boat to the foot of the lighthouse is 412.23 feet412.23{\text{ feet}}
So, the correct answer is “ 412.23 feet412.23{\text{ feet}}”.

Note : The term angle of depression means the angle from the horizontal downward to an object. To speed up the calculation in future, always remember the fact that the angle of depression is always measured from the horizontal and is not in the triangle. Also note that the angle of elevation and the angle of depression are always equal.