Question
Question: From the top of a cliff \(20m\) high, the angle of elevation of the top of a tower is found to be eq...
From the top of a cliff 20m high, the angle of elevation of the top of a tower is found to be equal to the angle of depression of the foot of a tower. Find the height of the tower.
Solution
The question belongs to the topic- heights and distances. In such questions, trigonometric ratios are used to find the required length or distance. Start by making a figure as per the question. Mark all the angles and lengths given. Find a relation between the given side and the side to be found. Using the relation between the two sides, use a suitable trigonometric ratio.
Complete step-by-step answer:
Start by making a diagram as per the question. Let CH be the cliff, AD be the tower whose length is to be found. We are given CH=20m. We can see
BD=CH=20m.
It is given that the two angles- one to the top of the tower and other to the bottom of the tower- are equal. Let ∠ACB=∠BCD=x∘.
In △BCD,
⇒tanx∘=BCBD
Putting BD=20m,
⇒tanx∘=BC20 …..…. (1)
In △ABC,
⇒tanx∘=BCAB ….…. (2)
Since LHS of equations (1) and (2) are same, we will equate them-
⇒BC20=BCAB
Shifting and solving,
⇒AB20=BCBC
⇒AB20=1
⇒AB=20m
Now, we know that tower = AB+BD =20m+20m=40m
Hence, the height of the tower is 40m.
Note: There are certain terms used in the question which are important to understand before solving any heights and distances question-
- Angle of elevation: It is the angle formed when we see an object above our eye level.
- Angle of depression: It is an angle formed when we see an object below our eye level.