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Question: From the top of a cliff \(20m\) high, the angle of elevation of the top of a tower is found to be eq...

From the top of a cliff 20m20m high, the angle of elevation of the top of a tower is found to be equal to the angle of depression of the foot of a tower. Find the height of the tower.

Explanation

Solution

The question belongs to the topic- heights and distances. In such questions, trigonometric ratios are used to find the required length or distance. Start by making a figure as per the question. Mark all the angles and lengths given. Find a relation between the given side and the side to be found. Using the relation between the two sides, use a suitable trigonometric ratio.

Complete step-by-step answer:
Start by making a diagram as per the question. Let CH be the cliff, AD be the tower whose length is to be found. We are given CH=20mCH = 20m. We can see

BD=CH=20mBD = CH = 20m.
It is given that the two angles- one to the top of the tower and other to the bottom of the tower- are equal. Let ACB=BCD=x\angle ACB = \angle BCD = x^\circ .
In BCD\vartriangle BCD,
tanx=BDBC\Rightarrow \tan x^\circ = \dfrac{{BD}}{{BC}}
Putting BD=20mBD = 20m,
tanx=20BC\Rightarrow \tan x^\circ = \dfrac{{20}}{{BC}} …..…. (1)
In ABC\vartriangle ABC,
tanx=ABBC\Rightarrow \tan x^\circ = \dfrac{{AB}}{{BC}} ….…. (2)
Since LHS of equations (1) and (2) are same, we will equate them-
20BC=ABBC\Rightarrow \dfrac{{20}}{{BC}} = \dfrac{{AB}}{{BC}}
Shifting and solving,
20AB=BCBC\Rightarrow \dfrac{{20}}{{AB}} = \dfrac{{BC}}{{BC}}
20AB=1\Rightarrow \dfrac{{20}}{{AB}} = 1
AB=20m\Rightarrow AB = 20m
Now, we know that tower = AB+BDAB + BD =20m+20m=40m = 20m + 20m = 40m

Hence, the height of the tower is 40m40m.

Note: There are certain terms used in the question which are important to understand before solving any heights and distances question-

  1. Angle of elevation: It is the angle formed when we see an object above our eye level.
  2. Angle of depression: It is an angle formed when we see an object below our eye level.