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Question: From the point P(1, \(\sqrt{2}\)) on the circle x<sup>2</sup> + y<sup>2</sup> = 4 a tangent is drawn...

From the point P(1, 2\sqrt{2}) on the circle x2 + y2 = 4 a tangent is drawn to the hyperbola x24y21=1\frac{x^{2}}{4} - \frac{y^{2}}{1} = 1 which meets its transverse axis at Q. From Q a line is drawn parallel to conjugate axis, which cuts the hyperbola at R above the x-axis, then PR equals

A

3

B

10\sqrt{10}

C

33+42\frac{3\sqrt{3} + 4}{2}

D

None of these

Answer

3

Explanation

Solution

P = (1, 3\sqrt{3}) = (2cosπ3,2sinπ3)\left( 2\cos\frac{\pi}{3},2\sin\frac{\pi}{3} \right)

Recall the definition of parametric point on hyperbola, we have

R = (2secπ3,1tanπ3)=(4,3)\left( 2\sec\frac{\pi}{3},1\tan\frac{\pi}{3} \right) = (4,\sqrt{3})

∴ PR = 4 - 1 = 3.