Question

From the following data of DH, of the following reactions,

C(s) + $\frac{1}{2}$O2 (g) $\longrightarrow$CO (g) $\Delta$H = – 110 kJ

C(s) + H2O (g) $\longrightarrow$CO (g) + H2(g) $\Delta$H = 132 kJ

What is the mole composition of the mixture of steam and oxygen on being passed over coke at 1273 K, to maintain constant temperature:

• A. 0.5 : 1
• B. 1 : 0.6
• C. 0.8 : 1
• D. 1 : 1

Answer 1

Answer: (B)

1 : 0.6

Answer 2

Let mixture contain x mole of steam & y mole oxygen then,

Here, temperature is constant. So, amount of heat released = amount of heat gain

x × 132 = y(220) $\Rightarrow$ $\frac{x}{y}$ = $\frac{220}{132}$ = $\frac{1.66}{1}$

$\Rightarrow$ y : x = 1 : 0.6