Question
Question: From the equation \(C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O\) i) what volume of carbon dioxide is pr...
From the equation CH4+2O2→CO2+2H2O
i) what volume of carbon dioxide is produced by 200cm3 of methane?
ii) What volume of Oxygen is required to completely burn 200cm3 of Methane?
Solution
Considering standard temperature and pressure (STP) conditions, we’ll consider the pressure to be 1 atmosphere and temperature to be 273.15K. At STP 1 mole of molecule occupies 22.4L of volume. This is the standard values we’ll consider for the given question.
Complete answer:
The given reaction is a combustion reaction. Combustion of hydrocarbons always leads to the formation of Carbon Dioxide and water. According to the balanced chemical reaction, we can infer that one mole of Methane required 2 moles of Oxygen to form 1 mol of Carbon Dioxide and 2 moles of water.
i) Given that we have taken 200cm3 of methane. 1 mole of methane produces only 1 mole of carbon dioxide. Hence, we can say that:
1mol CH4=1mol CO2
We know that one mole of molecule at STP occupies 22.4L of volume. We can say that,
22.4L CH4=22.4L CO2
200cm3 CH4=22.40.2×22.4=0.2L=200cm3of carbon dioxide.
ii) According to the balanced chemical equation 1mole of methane requires 2 moles of Oxygen. We can say that:
1mol CH2(22.4L)=2mol O2(2×22.4)
Therefore, 200cm3 or 0.2L of methane will require =22.40.2×2×22.4=0.4L=400cm3 of Oxygen.
Note:
According to Avogadro’s hypothesis at constant Pressure and Temperature, all gases contain the same number of particles. Since the number of particles are almost the same, the volume occupied by them will also be the same i.e., 22.4L . This volume will change when a gas is heated as the gas expands on heating, as the molecule moves at a faster rate. Also, change in pressure (expansion or compression) changes the volume of the gas. Hence, while making this assumption the Temperature and pressure is considered to be constant at 272.15K and 1 atmosphere respectively.