Question
Mathematics Question on Circle
From O(0, 0), two tangents OA and OB are drawn to a circle x2+y2−6x+4y+8=0, then the equation of circumcircle of
⃤ OAB.
A
x2 + y2 – 3x + 2y = 0
B
x2 + y2 + 3x – 2y = 0
C
x2 + y2 + 3x + 2y = 0
D
x2 + y2 – 3x – 2y = 0
Answer
x2 + y2 – 3x + 2y = 0
Explanation
Solution
The correct option is (A): x2 + y2 – 3x + 2y = 0