Solveeit Logo

Question

Question: From any point on a hyperbola xy = c<sup>2</sup> tangents are drawn to another hyperbola xy = a<sup>...

From any point on a hyperbola xy = c2 tangents are drawn to another hyperbola xy = a2 which has the same asymptotes. Then the chord of contact cuts off a constant area from the asymptotes:

A

2a2c2\frac{2a^{2}}{c^{2}}

B

a2c2\frac{a^{2}}{c^{2}}

C

2c2a2\frac{2c^{2}}{a^{2}}

D

c2a2\frac{c^{2}}{a^{2}}

Answer

2a2c2\frac{2a^{2}}{c^{2}}

Explanation

Solution

Let xy = c2 be the rectangular hyperbola referred to its asymptotes as the coordinate axis.

Let P(h, k) be a point on

xy = c2 ... (i)

tangents are drawn from P(h, k) to the rectangular hyperbola xy = a2

\ equation of chord of contact

Ž kx + hy = 2a2

This cuts the coordinate axis at A (2a2k,0)\left( \frac{2a^{2}}{k},0 \right)

and B (0,2a2h)\left( 0,\frac{2a^{2}}{h} \right)

\ Area of D OAB = 12\frac{1}{2} (2a2k×2a2h)\left( \frac{2a^{2}}{k} \times \frac{2a^{2}}{h} \right)

=2a4kh\frac{2a^{4}}{kh}= 2a2c2\frac{2a^{2}}{c^{2}}