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Question: From an external point P tangents are drawn to the parabola y<sup>2</sup> = 4ax, then the equation t...

From an external point P tangents are drawn to the parabola y2 = 4ax, then the equation to the locus of P when these tangents makes angles q1 and q2 with the axis, such that

tan q1 + tan q2 with the axis, such that tan q1 + tan q2 is constant (= b), is –

A

y = xb\frac{x}{b}

B

y = bx

C

y = b2 x

D

None of these

Answer

y = bx

Explanation

Solution

Let the coordinates of P be (h, k) and the equation to the parabola be y2 = 4ax. Any tangent on the parabola is given by y = mx + am\frac{a}{m}. If this passes through (h, k), the coordinates will satisfy. Hence

k = mh + am\frac{a}{m}.

Ž m2h – mk + a = 0 …(1)

Which is a quadratic in m . Let its roots be m1 and m2, then m1 + m2 = kh\frac{k}{h} and m1m2 = ah\frac{a}{h}. Now, if the two tangents through P make angles q1 and q2 with axis of x and m1 = tan q1 and m2 = tan q2.

\ tan q1 + tan q2 = kh\frac{k}{h}. … (2)

and m1m2 = ah\frac{a}{h} … (3)

Ž tan q1 tan q2 = ah\frac{a}{h} … (4)

By hypothesis tan q1 + tan q2 = b

So from equation (2), kh\frac{k}{h} = b Ž k = bh. Generalising, the locus of (h, k) is y = bx.

Hence (2) is correct answer.