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Question

Physics Question on System of Particles & Rotational Motion

From a uniform circular disc of radius RR and mass 9M9 \,M, a small disc of radius R3\frac{R}{3} is removed as shown in the figure. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through centre of disc is -

A

4MR24 MR^2

B

409MR2\frac{40}{9} MR^2

C

10MR210 MR^2

D

379MR2\frac{37}{9} MR^2

Answer

4MR24 MR^2

Explanation

Solution