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Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at le...

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are in the committee. In how many ways can it be done?

Explanation

Solution

Now in question it is asked to find the number of ways a committee can be formed so that there are, at least 3 men mean that there can be 3 men or 4 men or all of the 5 committee members as men. So, we will have three cases.
Case 1: When there are 3 men, then there will be 2 women.
Case 2: When there are 4 men, then there will be 1 woman.
Case 3: When there are 5 men, then there will be 0 women.
And for solving these cases we will use The formula for selecting r different things from n different things called as combination and is given asnCr=n!r!(nr)!{}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!} .
The formula for finding the number of ways for arranging n different things is given as=n!=n!, where n!=n(n1)(n2)....3.2.1n!=n(n-1)(n-2)....3.2.1.

Complete step-by-step answer:
As mentioned in the question, there will be 3 cases for calculating the number of ways to form a committee is as follows

Case 1: 3 Men, 2 Women
For selecting 3 men out of 7 and 2 women out of 6 to form thee 5 people committee, we can use the formulas given in the hint as follows
=7C3×6C2={}^{7}C{}_{3}\times {}^{6}C{}_{2}
=35×15=35\times 15
=525=525
Case 2: 4 Men, 1 Woman
For selecting 4 men out of 7 and 1 woman out of 6 to form thee 5 people committee, we can use the formulas given in the hint as follows
=7C4×6C1={}^{7}C{}_{4}\times {}^{6}C{}_{1}
=35×6=35\times 6
=210=210
Case 3: 5 Men, 0 Women
For selecting 5 men out of 7 and 0 women out of 6 to form thee 5 people committee, we can use the formulas given in the hint as follows
=7C5×6C0={}^{7}C{}_{5}\times {}^{6}C{}_{0}
=21×1=21\times 1
=21=21

Total =525+210+21 =756

Hence, the answer total number of ways to form a 5 member committee is 756.

Note: The students can make an error if they don’t know the fundamental theorem and the formula for selecting r different things from n different things which is given as nCr=n!r!(nr)!{}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}.
Try not to make any calculation errors as this will change the final answer.