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Question: From a group of 2 boys and 3 girls, two children are selected. Find the sample space of this experim...

From a group of 2 boys and 3 girls, two children are selected. Find the sample space of this experiment.

Explanation

Solution

First, we calculate the total number of possible ways to select 2 children at random using a method of combination. We form sample space for the given experiment by collecting each possibility of pairing two children be it both girls, both boys or a girl and a boy. Denote two boys as subscripts of B and three girls as subscripts of G. Make possible pairs of children.

  • Combination is given by nCr=n!(nr)!r!^n{C_r} = \dfrac{{n!}}{{(n - r)!r!}}where factorial opens up as n!=n(n1)!=n(n1)(n2)!....n! = n(n - 1)! = n(n - 1)(n - 2)!....
  • Sample space of an experiment is the set of all possible outcomes of a random experiment.

Complete step-by-step answer:
We are given there are 2 boys and 3 girls.
So, the total number of children is 5.
We first calculate the total number of ways to select 2 children from the total 5 children using the method of combination.
Number of ways of selecting 2 children out of 5 is 5C2^5{C_2}.
Here n=5,r=2n = 5,r = 2
5C2=5!(52)!2!{ \Rightarrow ^5}{C_2} = \dfrac{{5!}}{{(5 - 2)!2!}}
5C2=5×4×3!3!2!{ \Rightarrow ^5}{C_2} = \dfrac{{5 \times 4 \times 3!}}{{3!2!}}
Cancel same factors from numerator and denominator,
5C2=5×42{ \Rightarrow ^5}{C_2} = \dfrac{{5 \times 4}}{2}
Cancel same factors from numerator and denominator,
5C2=10{ \Rightarrow ^5}{C_2} = 10
So, there are 10 possible ways of selecting 2 children at random from a total 5 children.
Now let us assume 2 boys as B1,B2{B_1},{B_2} and 3 girls as G1,G2,G3{G_1},{G_2},{G_3}
We form 3 cases: both boys, both girls and one boy one girl,
CASE 1: Both boys
There are 2 boys B1,B2{B_1},{B_2}
We can only take one possibility when we choose both boys from 5 children i.e. B1B2{B_1}{B_2} … (1)
CASE 2: Both girls
There are 3 girls G1,G2,G3{G_1},{G_2},{G_3}
Possible combinations are: G1G2{G_1}{G_2}; G2G3{G_2}{G_3}and G1G3{G_1}{G_3} … (2)
CASE 3: One boy one girl
There are 3 girls G1,G2,G3{G_1},{G_2},{G_3}and 2 boys B1,B2{B_1},{B_2}
Possible combinations are: B1G1{B_1}{G_1}; B1G2{B_1}{G_2}; B1G3{B_1}{G_3}; B2G1{B_2}{G_1}; B2G2{B_2}{G_2}and B2G3{B_2}{G_3} … (3)
Now we combine all the possibilities to write the sample space for the experiment.
Let sample space of the experiment be denoted by S.
\Rightarrow S = \left\\{ {{B_1}{B_2},{G_1}{G_2},{G_2}{G_3},{G_1}{G_3},{B_1}{G_1},{B_1}{G_2},{B_1}{G_3},{B_2}{G_1},{B_2}{G_2},{B_2}{G_3}} \right\\}

\therefore Sample space for experiment is \left\\{ {{B_1}{B_2},{G_1}{G_2},{G_2}{G_3},{G_1}{G_3},{B_1}{G_1},{B_1}{G_2},{B_1}{G_3},{B_2}{G_1},{B_2}{G_2},{B_2}{G_3}} \right\\}

Note:
Many students make the mistake of writing the sample space with only three possibilities, each of a case which is wrong, even though we are not given which child we have to choose we have choices between which girl and which boy is chosen.