Question

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take $\pi$ = $\frac{22}{ 7}$ )

Answer 1

Area of bigger circle

= $\frac{22}{7}\times 14\times 14$

= $616 \; cm^2$

Area of 2 small circles = $2 × \pi r^2$

= $2\times \frac{22}{7}\times 3.5\times 3.5$

= $77 \; cm^2$

Area of rectangle = Length × Breadth
= $3 × 1 = 3$ $cm^2$
Remaining area of sheet
= $616 - 77 - 3$
= $536$ $cm^2$