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Question

Mathematics Question on Conditional Probability

From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is

A

1121\frac{11}{21}

B

521\frac{5}{21}

C

621\frac{6}{21}

D

121\frac{1}{21}

Answer

1121\frac{11}{21}

Explanation

Solution

n(S)=10C4;n(S) = ^{10}C_4; n(E) = 4 odd or 4 even or 2 Odd and 2 even; P(E)=1121P(E) = \frac{11}{21}