Solveeit Logo

Question

Physics Question on Motion in a straight line

From a balloon rising vertically upwards as 5m/s5\,m/s a stone is thrown up at 10m/s10 \,m/s relative to the balloon. Its velocity with respect to ground after 2s2\,s is (assume g=10m/s2g=10\,m/s^{2} )

A

zero

B

5m/s5\, m/s

C

10m/s10\,m/s

D

20m/s20\,m/s

Answer

5m/s5\, m/s

Explanation

Solution

The initial velocity with respect to ground will be 10+5=15m/s10+5=15 m / s
after 2 sec its velocity will be v=15gt=1510×2=5m/sv =15- gt =15-10 \times 2=-5 m / s
Whose value is 5m/s5 m / s
Once the stone is projected from balloon it will not have any impact of the balloon after that moment.