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Question: From \[4\] officers and \[8\] jawans, in how many ways can \[6\] be chosen such that it includes exa...

From 44 officers and 88 jawans, in how many ways can 66 be chosen such that it includes exactly one officer.

Explanation

Solution

Hint: Calculate the number of ways to choose 11 officers from 44 officers. Calculate the number of ways to choose 61=56-1=5 jawans from 88 jawans. Multiply both the values to calculate the total number of ways to choose 66 people.

Complete step-by-step answer:
We have a group of 44 officers and 88 jawans. We have to choose 66 people such that it includes exactly one officer. We have to find the number of ways to do so.
We will calculate the number of ways to choose one officer from 44 officers. Then we will calculate the number of ways to choose remaining people from 88 jawans. We will then multiply both the values to calculate the total number of ways to choose 66 people.
We know there are nCr{}^{n}{{C}_{r}} ways to choose rr people from a group of nn people. We know that nCr=n!r!(nr)!{}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}.
Substituting n=4,r=1n=4,r=1, we have 4C1=4!1!(3)!=4×3!3!=4{}^{4}{{C}_{1}}=\dfrac{4!}{1!\left( 3 \right)!}=\dfrac{4\times 3!}{3!}=4 ways to choose one officer from 44 officers.
As we have to choose total 66 people and we have already chosen one officer, the number of jawans to be chosen =61=5=6-1=5. So, we will now choose 55 jawans from 88 jawans.
Substituting n=8,r=5n=8,r=5, we have 8C5=8!5!(3)!=8×7×6×5!5!×3!=8×7×63×2=56{}^{8}{{C}_{5}}=\dfrac{8!}{5!\left( 3 \right)!}=\dfrac{8\times 7\times 6\times 5!}{5!\times 3!}=\dfrac{8\times 7\times 6}{3\times 2}=56 ways to choose 55 jawans from 88 jawans.
To calculate the total number of ways to choose 66 people according to the given data, we will multiply both the values of choosing one officer from 44 officers and 55 jawans from 88 jawans.
Thus, the total number of ways to choose 66 people according to the given data =4×56=224=4\times 56=224.
Hence, we can choose 66 people such that it includes exactly one officer is 224224.

Note: In this question, we are basically calculating all the possible combinations to choose people. One must keep in mind that we are not considering the arrangement of chosen people on this question. If we count the arrangement of people, we will get an incorrect answer.