Solveeit Logo

Question

Chemistry Question on Surface Chemistry

Freundlich adsorption isotherm equation is

A

logmx=logk+1nlogp\log \frac{m}{x}=\log k+\frac{1}{n}\log p

B

logxm=logk+nlogp\log \frac{x}{m}=\log k +n\log p

C

logmx=logk+nlogp\log \frac{m}{x}=\log k+n\log p

D

logxm=logk+1nlogp\log \frac{x}{m}=\log k+\frac{1}{n}\log p

Answer

logxm=logk+1nlogp\log \frac{x}{m}=\log k+\frac{1}{n}\log p

Explanation

Solution

Freundlich adsorption isotherm equation is as
logxm=logk+1nlogp\log \frac{x}{m}=\log \,k+\frac{1}{n}\log p
where xx is the mass of the gas adsorbed on mass mm of the adsorbent at pressure p.kp. k and nn are constants.