Question
Question: \frac{(x-a)(x-b)}{(c-a)(c-b)} + \frac{(x-b)(x-c)}{(a-b)(a-c)} + \frac{(x-c)(x-a)}{(b-c)(b-a)} = 1...
\frac{(x-a)(x-b)}{(c-a)(c-b)} + \frac{(x-b)(x-c)}{(a-b)(a-c)} + \frac{(x-c)(x-a)}{(b-c)(b-a)} = 1

Answer
False
Explanation
Solution
The given equation is a Lagrange interpolating polynomial. If a,b,c are distinct, the left-hand side is identically equal to 1 for all x. Thus, the equation becomes 1=1, which is true for all x, meaning it has infinitely many roots. Therefore, it does not have exactly two roots.
