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Question

Question: \frac{(x-a)(x-b)}{(c-a)(c-b)} + \frac{(x-b)(x-c)}{(a-b)(a-c)} + \frac{(x-c)(x-a)}{(b-c)(b-a)} = 1...

\frac{(x-a)(x-b)}{(c-a)(c-b)} + \frac{(x-b)(x-c)}{(a-b)(a-c)} + \frac{(x-c)(x-a)}{(b-c)(b-a)} = 1

Answer

False

Explanation

Solution

The given equation is a Lagrange interpolating polynomial. If a,b,ca, b, c are distinct, the left-hand side is identically equal to 1 for all xx. Thus, the equation becomes 1=11=1, which is true for all xx, meaning it has infinitely many roots. Therefore, it does not have exactly two roots.