Question
Question: \[\frac{\sin 2x}{2} + c\]...
2sin2x+c
A
2cos2x+c
B
∫x(x2+1)(x+1)2dx
C
logex+c
D
None of these
Answer
logex+c
Explanation
Solution
log(tanx)+c
sec(logx)6mu.6mutan(logx)+c
{Putting ∫xlogxlog(logx)dx=,
⇒ 2log(logx)+c
2sin2x+c
2cos2x+c
∫x(x2+1)(x+1)2dx
logex+c
None of these
logex+c
log(tanx)+c
sec(logx)6mu.6mutan(logx)+c
{Putting ∫xlogxlog(logx)dx=,
⇒ 2log(logx)+c