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Question

Question: $\frac{K_{P_1}}{K_{P_2}}=\frac{(n)^n \cdot P_1^{\Delta \nu_1}}{(m+k)^{(m+k)} \cdot P_2^{\Delta \nu_2...

KP1KP2=(n)nP1Δν1(m+k)(m+k)P2Δν2\frac{K_{P_1}}{K_{P_2}}=\frac{(n)^n \cdot P_1^{\Delta \nu_1}}{(m+k)^{(m+k)} \cdot P_2^{\Delta \nu_2}}

Answer

KP1KP2=(n)nP1Δν1(m+k)(m+k)P2Δν2\frac{K_{P_1}}{K_{P_2}}=\frac{(n)^n \cdot P_1^{\Delta \nu_1}}{(m+k)^{(m+k)} \cdot P_2^{\Delta \nu_2}}

Explanation

Solution

The given expression is:

KP1KP2=(n)nP1Δν1(m+k)(m+k)P2Δν2\frac{K_{P_1}}{K_{P_2}}=\frac{(n)^n \cdot P_1^{\Delta \nu_1}}{(m+k)^{(m+k)} \cdot P_2^{\Delta \nu_2}}

This equation represents a ratio of two equilibrium constants, KP1K_{P_1} and KP2K_{P_2}, for two different chemical reactions or the same reaction under two different sets of conditions (e.g., total pressures P1P_1 and P2P_2).

In this context:

  • KP1K_{P_1} and KP2K_{P_2} are the equilibrium constants in terms of partial pressures for reaction 1 and reaction 2, respectively.
  • P1P_1 and P2P_2 are the total pressures at which reaction 1 and reaction 2, respectively, reach equilibrium.
  • nn represents the number of moles of gaseous products formed from one mole of reactant in the first reaction (e.g., if AnBA \rightleftharpoons nB).
  • Δν1\Delta \nu_1 (or Δng1\Delta n_{g1}) is the change in the number of moles of gaseous products minus gaseous reactants for the first reaction.
  • (m+k)(m+k) represents the number of moles of gaseous products formed from one mole of reactant in the second reaction (e.g., if CmD+kEC \rightleftharpoons mD + kE, then nproducts=m+kn_{products} = m+k).
  • Δν2\Delta \nu_2 (or Δng2\Delta n_{g2}) is the change in the number of moles of gaseous products minus gaseous reactants for the second reaction.

This specific form of the expression suggests that certain terms related to the degree of dissociation (α\alpha) have either cancelled out or are assumed to be constant (e.g., equal to 1) in the derivation of this ratio. It is a formula used to compare equilibrium constants under varying pressures and stoichiometric changes.

The question asks for the solution to the given expression. As it is already an expression representing a relationship, the solution is the expression itself and its interpretation in the context of chemical equilibrium.

No specific numerical answer or simplification is possible without further context or values for the variables.