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Question

Question: $\frac{dy}{dx}=y \tan x - 2 \sin x$...

dydx=ytanx2sinx\frac{dy}{dx}=y \tan x - 2 \sin x

Answer

y=cosx+Ksecxy = \cos x + K \sec x

Explanation

Solution

The given differential equation is converted into the standard linear form dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x). The integrating factor (IF) eP(x)dxe^{\int P(x) dx} is calculated. The general solution y×IF=(Q(x)×IF)dx+Cy \times IF = \int (Q(x) \times IF) dx + C is then applied, and the resulting integral is evaluated using trigonometric identities. Finally, the equation is solved for yy.