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Question: \[\frac{\cos 12^{o} - \sin 12^{o}}{\cos 12^{o} + \sin 12^{o}} + \frac{\sin 147^{o}}{\cos 147^{o}} =\...

cos⁡12o−sin⁡12ocos⁡12o+sin⁡12o+sin⁡147ocos⁡147o=\frac{\cos 12^{o} - \sin 12^{o}}{\cos 12^{o} + \sin 12^{o}} + \frac{\sin 147^{o}}{\cos 147^{o}} =

A

2tan⁡33o2\tan 33^{o}

B

1

C

– 1

D

0

Answer

0

Explanation

Solution

= 1−tan⁡12o1+tan⁡12o+tan⁡147o\frac{1 - \tan 12^{o}}{1 + \tan 12^{o}} + \tan 147^{o}

= tan⁡(45o−12)+tan⁡(180o−33o)=tan⁡33o+(−tan⁡33o)=0\tan(45^{o} - 12) + \tan(180^{o} - 33^{o}) = \tan 33^{o} + ( - \tan 33^{o}) = 0.