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Question

Question: \[\frac{\cos 10^{o} + \sin 10^{o}}{\cos 10^{o} - \sin 10^{o}} =\]...

cos⁡10o+sin⁡10ocos⁡10o−sin⁡10o=\frac{\cos 10^{o} + \sin 10^{o}}{\cos 10^{o} - \sin 10^{o}} =

A

tan⁡55o\tan 55^{o}

B

cot⁡55o\cot 55^{o}

C

−tan⁡35o- \tan 35^{o}

D

−cot⁡35o- \cot 35^{o}

Answer

tan⁡55o\tan 55^{o}

Explanation

Solution

cos⁡10o+sin⁡10ocos⁡10o−sin⁡10o=tan⁡(45o+10o)=tan⁡55o\frac{\cos 10^{o} + \sin 10^{o}}{\cos 10^{o} - \sin 10^{o}} = \tan(45^{o} + 10^{o}) = \tan 55^{o}.