\[\frac{2}{\sqrt{\tan x}} + c] | MATH - INTEGRATION BY SUBSTITUTION | SolveeIt

$\frac{2}{\sqrt{\tan x}} + c$

$\frac{2}{\sqrt{\sec x}} + c$

$\int_{}^{}\frac{\sin 2x}{a^{2} + b^{2}\sin^{2}x}\mspace{6mu} dx =$

$\frac{1}{b^{2}}\log(a^{2} + b^{2}\sin^{2}x) + c$

$\frac{1}{b}\log(a^{2} + b^{2}\sin^{2}x) + c$

Answer

$\int_{}^{}\frac{\sin 2x}{a^{2} + b^{2}\sin^{2}x}\mspace{6mu} dx =$

Explanation

Put $(1 + x)^{- 1} + c$ therefore

$(1 - x)^{- 1} + c$ .

Question: \[\frac{2}{\sqrt{\tan x}} + c\]...