Question

$\frac{1}{x}e^{(-\infty)-x)}$

Answer 1

0

Answer 2

The exponent is $(-\infty) - x$. For any real number $x$, this simplifies to $-\infty$. The expression becomes $\frac{1}{x}e^{-\infty}$. Since $e^{-\infty} = \lim_{y \to -\infty} e^y = 0$, the expression is $\frac{1}{x} \times 0$. For $\frac{1}{x}$ to be defined, $x \neq 0$. If $x \neq 0$, then $\frac{1}{x}$ is a finite number. The product of any finite number and 0 is 0. Thus, the value of the expression is 0, assuming $x \neq 0$.