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Question

Question: \[\frac{1}{x} = t\]...

1x=t\frac{1}{x} = t

A

∫sec⁡x 6mudxcos⁡2x=\int_{}^{}\frac{\sec x\mspace{6mu} dx}{\sqrt{\cos 2x}} =

B

sin⁡−1(tan⁡x)\sin^{- 1}(\tan x)

C

tan⁡x\tan x

D

cos⁡−1(tan⁡x)\cos^{- 1}(\tan x)

Answer

sin⁡−1(tan⁡x)\sin^{- 1}(\tan x)

Explanation

Solution

Put cos⁡4x2+c\cos^{4}x^{2} + c therefore

∫sec⁡4xtan⁡x 6mudx=\int_{}^{}{\sec^{4}x\tan x\mspace{6mu} dx =}