\[\frac{1}{(\log a)^{2}}\sin a^{x} + c] | MATH - FUNDAMENTAL INTEGRATION | SolveeIt

$\frac{1}{(\log a)^{2}}\sin a^{x} + c$

${logsin}a^{x} + c$

$\int_{}^{}{\frac{\sin x\mspace{6mu} dx}{(a + b\cos x)^{2}} =}$

$\frac{1}{b}(a + b\cos x) + c$

$\frac{1}{b(a + b\cos x)} + c$

Answer

${logsin}a^{x} + c$

Explanation

$\int_{}^{}{\frac{1}{\sqrt{x}}\tan^{4}\sqrt{x}}\sec^{2}\sqrt{x}\mspace{6mu} dx =$

$2\tan^{5}\sqrt{x} + c$

$\frac{1}{5}\tan^{5}\sqrt{x} + c$

$\frac{2}{5}\tan^{5}\sqrt{x} + c$

Question: \[\frac{1}{(\log a)^{2}}\sin a^{x} + c\]...