Question
Question: \(\frac{1}{b}\log(a + b\cos x) + c\)...
b1log(a+bcosx)+c
A
∫x31[logxx]26mudx=
B
3x3(logx)+x+c
C
31(logx)3+c
D
3log(logx)+c
Answer
∫x31[logxx]26mudx=
Explanation
Solution
∫1−a2xaxdx=
loga1sin−1ax+c
sin−1ax+c.
b1log(a+bcosx)+c
∫x31[logxx]26mudx=
3x3(logx)+x+c
31(logx)3+c
3log(logx)+c
∫x31[logxx]26mudx=
∫1−a2xaxdx=
loga1sin−1ax+c
sin−1ax+c.