\[\frac{1}{6}\log\lbrack\sec 6x + \tan 6x\rbrack + c] | MATH - FUNDAMENTAL INTEGRATION | SolveeIt | Solveeit

Today, August 23

Question

$\frac{1}{6}\log\lbrack\sec 6x + \tan 6x\rbrack + c$

A

$\log\lbrack\sec 6x + \tan 6x\rbrack + c$

B

$\int_{}^{}{\frac{\sin 3x}{\sin x}\mspace{6mu} dx =}$

C

$x + \sin 2x + c$

D

$3x + \sin 2x + c$

Answer

$x + \sin 2x + c$

Explanation

Solution

$\sec^{3}x - \sec x + c$