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Question

Question: \(\frac{1}{4}\cos^{4}x^{2} + c\)...

14cos4x2+c\frac{1}{4}\cos^{4}x^{2} + c

A

cos4x2+c\cos^{4}x^{2} + c

B

sec4xtanx6mudx=\int_{}^{}{\sec^{4}x\tan x\mspace{6mu} dx =}

C

14sec4x+c\frac{1}{4}\sec^{4}x + c

D

None of these

Answer

cos4x2+c\cos^{4}x^{2} + c

Explanation

Solution

1(1+tanx)2+c- \frac{1}{(1 + \tan x)^{2}} + c

e2x1e2x+16mudx=\int_{}^{}\frac{e^{2x} - 1}{e^{2x} + 1}\mspace{6mu} dx =.