\[\frac{1}{2}\tan^{- 1}\left( \frac{2x}{3} \right) + c] | MATH - INTEGRATION BY SUBSTITUTION | SolveeIt | Solveeit

Today, August 18

Question

$\frac{1}{2}\tan^{- 1}\left( \frac{2x}{3} \right) + c$

A

$\frac{3}{2}\tan^{- 1}\left( \frac{2x}{3} \right) + c$

B

$\frac{1}{6}\tan^{- 1}\left( \frac{2x}{3} \right) + c$

C

$\frac{1}{6}\tan^{- 1}\left( \frac{3x}{2} \right) + c$

D

$\int_{}^{}{\frac{dx}{1 + e^{x}} =}$

Answer

$\frac{1}{6}\tan^{- 1}\left( \frac{3x}{2} \right) + c$

Explanation

Solution

Put $2\lbrack\tan^{- 1}x^{2}\rbrack^{2} + c$ .