Question
Question: \[\frac{1}{2}\log(1 + \sin^{2}x) + c\]...
21log(1+sin2x)+c
A
tan−1(sinx)+c
B
∫x2+2x3dx=
C
31(x2+2)3/2+2(x2+2)1/2+c
D
31(x2+2)3/2−2(x2+2)1/2+c
Answer
∫x2+2x3dx=
Explanation
Solution
8sin4xcos2x+c
Now put 4sin4x+c
then it reduces to 2sin2x+c
4sin4x+c.