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Question

Question: \(\frac{1}{2}\frac{1}{(10^{x} + x^{10})^{2}} + c\)...

121(10x+x10)2+c\frac{1}{2}\frac{1}{(10^{x} + x^{10})^{2}} + c

A

1(ex+ex)26mudx=\int_{}^{}{\frac{1}{(e^{x} + e^{- x})^{2}}\mspace{6mu} dx =}

B

12(e2x+1)+c- \frac{1}{2(e^{2x} + 1)} + c

C

12(e2x+1)+c\frac{1}{2(e^{2x} + 1)} + c

D

None of these

Answer

1(ex+ex)26mudx=\int_{}^{}{\frac{1}{(e^{x} + e^{- x})^{2}}\mspace{6mu} dx =}

Explanation

Solution

tanx+c\tan x + c

Put sin3x+cos3xsin2xcos2x6mudx=\int_{}^{}\frac{\sin^{3}x + \cos^{3}x}{\sin^{2}x\cos^{2}x}\mspace{6mu} dx =, then it reduces to

tanx+cotx+c\tan x + \cot x + c

tanxcotx+c\tan x - \cot x + c.