Question
Question: \(\frac{1^{2}.2}{1!} + \frac{2^{2}.3}{2!} + \frac{3^{2}.4}{3!} + .....\infty =\)\]...
1!12.2+2!22.3+3!32.4+.....∞=]
A
6e
B
7e
C
8e
D
9e
Answer
7e
Explanation
Solution
6(log3)3
Here 3!3
12.31+23.91+34.271+45.811+......∞=
21−loge32
−loge32.