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Question: \[\frac{1}{1.3} + \frac{1}{2}.\frac{1}{3.5} + \frac{1}{3}.\frac{1}{5.7} + ......\infty =\]...

11.3+12.13.5+13.15.7+......∞=\frac{1}{1.3} + \frac{1}{2}.\frac{1}{3.5} + \frac{1}{3}.\frac{1}{5.7} + ......\infty =

A

2log⁡e2−12\log_{e}2 - 1

B

log⁡e2−1\log_{e}2 - 1

C

log⁡e2\log_{e}2

D

None of these

Answer

2log⁡e2−12\log_{e}2 - 1

Explanation

Solution

eeb/a\frac{e}{e^{b/a}}

eea/b\frac{e}{e^{a/b}} .