Question

$\frac{1}{1 - \tan x} + c$

• A. $- \frac{1}{3}\frac{1}{(1 - \tan x)^{3}} + c$
• B. $\int_{}^{}\frac{10x^{9} + 10^{x}\log_{e}10}{10^{x} + x^{10}}\mspace{6mu} dx =$
• C. $- \frac{1}{2}\frac{1}{(10^{x} + x^{10})^{2}} + c$
• D. $\log(10^{x} + x^{10}) + c$

Answer 1

Answer: (B)

$\int_{}^{}\frac{10x^{9} + 10^{x}\log_{e}10}{10^{x} + x^{10}}\mspace{6mu} dx =$

Answer 2

$\sec^{- 1}x + c$

Multiplying $\cot^{- 1}x + c$ and $\tan^{- 1}x + c$ by $\int_{}^{}{\frac{\cos 2x + 2\sin^{2}x}{\cos^{2}x}dx =}$ we get

{Putting $2\sec x + c$

$2\tan x + c$.